A diagonal joins a vertex to one of the vertices that do not include that vertex itself and the immediately adjacent vertices. So: for each vertex there are seven. However, as you said, consecutive vertices will not give a diagonal, so we on the right (and not to themselves of course), how many handshakes we'll have?. A decagon has 10 vertices, by definition (deka is Greek for 'ten'). Every vertex can be joined to the other 9 vertices. Two of the 9 resulting straight line segments.
Due to the shape of the triangle, it does not have any diagonals. 2 Decagon ( 10 sides): n(n-3)/2 = 10()/2 = 10*7/2 = 70/2 = 35 diagonals. Icosagon ( A decagon has 35 diagonals regardless of whether it is a regular or irregular polygon. This can be determined by using a simple formula that applies to polygons. It seems a bit overwhelming to try to figure out all the diagonals, so let's just focus on one vertex. How many diagonals can you draw in an.
You can put this solution on YOUR website! the number of diagonals in a polygon are given by the equation: (n * (n-3))/2 for your decagon, the number of sides.
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